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Acceleration of a particle is given by a = t3 - 3t2+ 5, where t = time in seconds and a =acceleration in m/s2. Velocity of the particlewhen t = 2 sec is 8 m/s. velocity of the particlewhen t = 4 sec isans.22 m/s32 m/s25 m/s28 m/s |
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Answer» Answer: The answer is 32 m/s. Explanation: a = t^3 - 3t^2 On DIFFERENTIATING, ∆v = 3t^2 - 6T v - 8 = 3 × ( 4^2 - 2^2 ) - ( 6×4 - 6×2 ) v - 8 = 3 × ( 16 - 4 ) - ( 24 - 12 ) v = 36 - 12 + 8 v = 24 + 8 v = 32 m/s |
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