1.

Acceleration of a particle is given by a = t3 - 3t2+ 5, where t = time in seconds and a =acceleration in m/s2. Velocity of the particlewhen t = 2 sec is 8 m/s. velocity of the particlewhen t = 4 sec isans.22 m/s32 m/s25 m/s28 m/s​

Answer»

Answer:

The answer is 32 m/s.

Explanation:

a = t^3 - 3t^2

On DIFFERENTIATING,

∆v = 3t^2 - 6T

v - 8 = 3 × ( 4^2 - 2^2 ) - ( 6×4 - 6×2 )

v - 8 = 3 × ( 16 - 4 ) - ( 24 - 12 )

v = 36 - 12 + 8

v = 24 + 8

v = 32 m/s



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