Acceleration of a particle a= -bx, where x is the displacement of particle from mean position and b is constant. What is the periodic time of oscillation ?

Acceleration of a particle a= -bx, where x is the displacement of part

1.	Acceleration of a particle a= -bx, where x is the displacement of particle from mean position and b is constant. What is the periodic time of oscillation ?
Answer» `2pi SQRT(b)` `(2pi)/(sqrt(b))` `(2pi)/(b)` `2 sqrt(((pi)/(b))` SOLUTION :COMPARING `a= -kx` with `a= -omega^(2)x, omega^(2)= b` `THEREFORE omega = sqrt(b)` `therefore (2pi)/(T)= sqrt(b)` `therefore T= (2pi)/(sqrt(b))`.