1.

Abus travelled from village A to village B at a speed of 40 km per hour. On thereturn journey its speed was 60 km per hour. What is the average speed of thebus during the entire journey?(1) 50 km/h (2) 48 km/h (3) 46 km/h (4) 45 km/h​

Answer»

Given :

• A bus travelled from village A to village B at a speed of 40 km per hour.

• On the return journey its speed was 60 km per hour.

To calculate :

• Average speed during the entire journey.

Calculation :

Let the distance from A to B be d km.

We know that,

\bigstar \: \boxed{\sf {Average \: Speed = \dfrac{<klux>TOTAL</klux> \: Distance}{Total \: time \: taken} }} \\

\underline{ \underline{ \sf \red {Calculating \: total \: distance \: \: :}} }

Firstly it travels from A to village B and then it returns from B to A.

➠ Distance from A to B = d

➠ Distance from B to A = d

➛ Total Distance = Distance from A to B + Distance from B to A

➛ Total Distance = ( d + d ) km

Total Distance = 2d km

\underline{ \underline{ \sf \red{Calculating \: total \: time \: \: :}} }

As we know that,

\bigstar \: \boxed{\sf { Time = \dfrac{Distance}{Speed} }} \\

Time taken to COVER the distance from A to B (t₁):

➠ t₁ = \sf { \dfrac{d}{40} } hrs

Time taken to cover the distance from B to A (t):

➠ t₂ = \sf { \dfrac{d}{60} } hrs

➛ Total time = t₁ + t₂

➛ Total time = \sf {  \dfrac{d}{40} + \dfrac{d}{60} } hrs

➛ Total time = \sf {  \dfrac{3d + 2d}{120} } hrs

➛ Total time = \sf {  \dfrac{5d}{120} } hrs

➛ Total time = \sf {  \dfrac{1d}{24} } hrs

\sf {  \dfrac{d}{24} }➛ Total time = hrs

Now, SUBSTITUTING the VALUES in the formula of average speed to find the average speed of the bus during the entire journey.

\bigstar \: \boxed{\sf {Average \: Speed = \dfrac{Total \: Distance}{Total \: time \: taken} }} \\

➛ Average speed = \sf{ \dfrac{2d}{ \cfrac{d}{24} }} km/h

➛ Average speed = \sf{ 2 \not{d} \times \dfrac{24}{\not{d}}} km/h

➛ Average speed = \sf{ 2 \times 24 } km/h

➛ Average speed = 48 km/h

Therefore, average speed of the bus during the entire journey is 48 km/h. Option is correct.



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