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Abhay jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another minute. What is the average velocity and speed in jogging from A to B and from A to C? |
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Answer» HEY friend!!!!!! Velocity = dispacement / time Speed = distance / time a) when he jogs from A to B on a STRAIGHT road, => displacement = distance = 300m => time = 2 minutes 30 seconds = 150 s => velocity = 300/150 = 2 m/s => speed = 300/150 = 2m/s b)when he jogs from A to B and TURNS back to C, => displacement = 300-100 = 200m => distance = 300+100 = 400m => time = 3 minute 30 second = 210 s => velocity = 200/210 = 20/21 m/s => speed = 400/210 = 40/21 m/s hope it will HELP you |
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