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ABCDEF is a regular hexagon with point O as centre. Find the value of vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF). |
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Answer» SOLUTION :From the diagram `(vec(AB)=-vec(DE))(vec(BC)=-vec(EF))` `vec(AB)+vec(AC)+vec(AD)+vec(AE)+vec(AF)` `=cancelvec(AB)+(cancelvec(AB)+cancelvec(BC))+vec(AD)+(cancelvec(AD)+cancelvec(DE))+(vec(AD)+cancelvec(DE)+cancelvec(EF))` `=3vec(AD)=3(2vec(AO))=6(vec(AO))` |
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