ABCD is rectangle. On side DC a semicircle is drawn.From the informati

1.	ABCD is rectangle. On side DC a semicircle is drawn.From the information given in the figure, find out area ofshaded portion.
Answer» Answer: area of ABC rect =lB 117 77 area of semi circle = πr^2 22/73.53.5/2 220.53.5/2 38.5/2 19.25 area of unshaded rect = l b 75 35 area of shaded portion =77- (19.25+35) =22.75 hope it might be right

ABCD is rectangle. On side DC a semicircle is drawn.From the information given in the figure, find out area ofshaded portion.

Answer»

Answer:

area of ABC rect =l*B

11*7

area of semi circle = πr^2

22/7*3.5*3.5/2

22*0.5*3.5/2

38.5/2

19.25

area of unshaded rect = l *b

7*5

area of shaded portion =77-

(19.25+35)

=22.75

hope it might be right

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ABCD is rectangle. On side DC a semicircle is drawn.From the information given in the figure, find out area ofshaded portion. ​

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ABCD is rectangle. On side DC a semicircle is drawn.From the information given in the figure, find out area ofshaded portion.