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`ABCD` is a square in first quadrant whose side is a, taking `AB and AD` as axes, prove that the equation to the circle circumscribing the square is `x^2+ y^2= a(x + y)`.A. `x^(2)+y^(2)+ax-ay=0`B. `x^(2)+y^(2)-ax+ay=0`C. `x^(2)+y^(2)-ax-ay=0`D. `x^(2)+y^(2)+ax-ay=0` |
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Answer» Correct Answer - C |
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