ABCD is a square and the diagonals intersect at O. If P is a point on AB such that AO=AP, prove that 3(angle POB)=(angle AOP).

ABCD is a square and the diagonals intersect at O. If P is a point on

1.	ABCD is a square and the diagonals intersect at O. If P is a point on AB such that AO=AP, prove that 3(angle POB)=(angle AOP).
Answer» ABCD is a square and the diagonals intersect at O. If P is a point on AB such that AO=AP, prove that 3(angle POB)=(angle AOP).