ABCD is a rhombus and P, Q, R, S are mid-points of AB, BC, CD and DA r

1.	ABCD is a rhombus and P, Q, R, S are mid-points of AB, BC, CD and DA respectively. Prove thatquadrilateral PQRS is a rectangle.
Answer» Answer: Given- ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove-PQRS is a rectangle Construction, AC and BD are joined. Proof, In ΔDRS and ΔBPQ, DS = BQ (HALVES of the opposite sides of the rhombus) ∠SDR = ∠QBP (Opposite angles of the rhombus) DR = BP (Halves of the opposite sides of the rhombus) THUS, ΔDRS ≅ ΔBPQ by SAS congruence condition. RS = PQ by CPCT --- (i) In ΔQCR and ΔSAP, RC = PA (Halves of the opposite sides of the rhombus) ∠RCQ = ∠PAS (Opposite angles of the rhombus) CQ = AS (Halves of the opposite sides of the rhombus) Thus, ΔQCR ≅ ΔSAP by SAS congruence condition. RQ = SP by CPCT --- (ii) Now, In ΔCDB, R and Q are the mid points of CD and BC respectively. ⇒ QR \|\| BD ALSO, P and S are the mid points of AD and AB respectively. ⇒ PS \|\| BD ⇒ QR \|\| PS Thus, PQRS is a parallelogram. also, ∠PQR = 90° Now, In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° Thus, PQRS is a rectangle.

ABCD is a rhombus and P, Q, R, S are mid-points of AB, BC, CD and DA respectively. Prove thatquadrilateral PQRS is a rectangle.

Answer»

Answer:

Given- ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively.

To Prove-PQRS is a rectangle

Construction,

AC and BD are joined.

Proof,

In ΔDRS and ΔBPQ,

DS = BQ (HALVES of the opposite sides of the rhombus)

∠SDR = ∠QBP (Opposite angles of the rhombus)

DR = BP (Halves of the opposite sides of the rhombus)

THUS, ΔDRS ≅ ΔBPQ by SAS congruence condition.

RS = PQ by CPCT --- (i)

In ΔQCR and ΔSAP,

RC = PA (Halves of the opposite sides of the rhombus)

∠RCQ = ∠PAS (Opposite angles of the rhombus)

CQ = AS (Halves of the opposite sides of the rhombus)

Thus, ΔQCR ≅ ΔSAP by SAS congruence condition.

RQ = SP by CPCT --- (ii)

Now,

In ΔCDB,

R and Q are the mid points of CD and BC respectively.

⇒ QR || BD

P and S are the mid points of AD and AB respectively.

⇒ PS || BD

⇒ QR || PS

Thus, PQRS is a parallelogram.

also, ∠PQR = 90°

Now,

In PQRS,

RS = PQ and RQ = SP from (i) and (ii)

∠Q = 90°

Thus, PQRS is a rectangle.