1.

ABCD is a rectangle. BD is the diagonal of the rectangle.Which all congruence criterion can be used to show triangle ABD congurent triangle BCD. (RHS, SSS ,ASA ,SAS can be congruent by all congurance condition)

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Answer:

SOLUTION:

To prove :In rectangle ABCD, TRIANGLE ABD is congruent to triangle BCD.

Proof: In triangle ABD and BCD,

AD=BC. (OPPOSITE sides of rectangle)

AB=CD.(oppposite sides of rectngle)

BD= BD (common)

triangle ABD is congruent to triangle BCD. (SSS-Side side side)



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