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ABCD is a quadrilateral prove that (AB+BC+CD+DA) >(AC+BD) ​

Answer»

ong>Answer:

Step-by-step EXPLANATION:ABCD is a quadrilateral and AC, and BD are the diagonals.

SUM of the two SIDES of a TRIANGLE is greater than the third side.

So, considering the triangle ABC, BCD, CAD and BAD, we get

AB + BC > AC

CD + AD > AC

AB + AD > BD

BC + CD > BD

Adding all the above equations,

2(AB + BC + CA + AD) > 2(AC + BD)

⇒ 2(AB + BC + CA + AD) > 2(AC + BD)

⇒ (AB + BC + CA + AD) > (AC + BD)

HENCE, PROVED



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