1.

ABCD is a parallelogram.P is a point on CD .if area of ∆APB= 8cm sq. find the area of parallelogram ABCD.

Answer»
  • AREA of TRIANGLE APB = area of triangle ADP
  • [two triangles having same base and LIE between same parallels]
  • = 8 CM sq.
  • Similarly, ar(triangle APB) = at(triangle BPC)
  • Therefore,ar(ABCD) = ar(ABP) + ar(ADP) +

ar(BPC)

  • = 8 + 8 + 8
  • = 24 cm sq.


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