Abcd is a parallelogram in which perpendicular bp and dq are drawn on

1.	Abcd is a parallelogram in which perpendicular bp and dq are drawn on the diagonal ac from the point b and d respectively prove that bpdq is a parallelogram
Answer» ong>Answer: It is GIVEN that in parallelogram ABCD, BP is perpendicular to AC and DQ is perpendicular to AC. In ΔADQ and ΔCBP, AD=CD (OPPOSITE sides of a parallelogram) ∠DAQ=∠BCP and AD∣∣BC,AC (Transversal alternate angles) ∠DQA=∠BPC=90 0 (Given) ⸫ΔADQ=ΔCBP (SAA) ⸫BP=DQ (C.P.C.T) Hence proved.

Abcd is a parallelogram in which perpendicular bp and dq are drawn on the diagonal ac from the point b and d respectively prove that bpdq is a parallelogram

Answer»

ong>Answer:

It is GIVEN that in parallelogram ABCD, BP is perpendicular to AC and DQ is perpendicular to AC.

In ΔADQ and ΔCBP,

AD=CD (OPPOSITE sides of a parallelogram)

∠DAQ=∠BCP and AD∣∣BC,AC (Transversal alternate angles)

∠DQA=∠BPC=90

(Given)

⸫ΔADQ=ΔCBP (SAA)

⸫BP=DQ (C.P.C.T)

Hence proved.

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Abcd is a parallelogram in which perpendicular bp and dq are drawn on the diagonal ac from the point b and d respectively prove that bpdq is a parallelogram​

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Abcd is a parallelogram in which perpendicular bp and dq are drawn on the diagonal ac from the point b and d respectively prove that bpdq is a parallelogram