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ABCD is a parallelogram find 1) < ABO 2) |
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Answer» ∠ABO= ∠ODC= ∠ACB= ∠CBD= Step-by-step EXPLANATION: ∠AOB=65° [V.O.A] In ΔAOB, ∠OAB+∠ABO+∠AOB=180°[A.S.P] 35°+∠ABO+65°=180° 100°+∠ABO=180° ∠ABO=80° In ΔODC, 65°+35°+∠ODC=180°[A.S.P] ∠ODC=80°
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