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ABCD is a parallelogram, angle D = 120°, AB = 10, AC = 12. Calculate the area of the parallelogram. |
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Answer» Area of the parallelogram = \(\frac{1}{2}\) × AC × BD In ΔABD, ∠A = 60° ΔABD is an equilateral triangle. BD = 10 Area of the parallelogram ABCD = \(\frac{1}{2}\) × 10 × 12 = 60m2 |
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