1.

ABCD is a parallelogram, angle D = 120°, AB = 10, AC = 12. Calculate the area of the parallelogram.

Answer»

Area of the parallelogram = \(\frac{1}{2}\) × AC × BD

In ΔABD, ∠A = 60°

ΔABD is an equilateral triangle.

BD = 10

Area of the parallelogram ABCD = \(\frac{1}{2}\) × 10 × 12 = 60m2



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