1.

∆ABC ∼ ∆PQR such that ar(∆ABC) = 4 ar(∆PQR). If BC = 12 cm, then QR =(a) 9 cm(b) 10 cm(c) 6 cm(d) 8 cm

Answer» ∆ABC ∼ ∆PQR such that ar(∆ABC) = 4 ar(∆PQR). If BC = 12 cm, then QR =



(a) 9 cm

(b) 10 cm

(c) 6 cm

(d) 8 cm


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