∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2=

1.	∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2= BD.CD.If AD= 4 cm and BD =2 cm, Find BC.
Answer» ANSWER: In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADC So

∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2= BD.CD.If AD= 4 cm and BD =2 cm, Find BC.

Answer»

In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADC So

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∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2= BD.CD.If AD= 4 cm and BD =2 cm, Find BC.​

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∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2= BD.CD.If AD= 4 cm and BD =2 cm, Find BC.