1.

∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm. The height AD from A to BC, is 6 cm. Find the area of ∆ABC. What will be the height from C to AB i.e; CE?​Note: - Diagram in Attachment - Need Quality Answer - Don't Spam!​

Answer» WER :-

Given :-

  • AB = AC = 7.5 cm
  • BC = 9 cm
  • AD = 6 cm

To Find :-

  • CE

Solution :-

Here, we have side BC and it's altitude AD. So, we will first find AREA of the TRIANGLE -

→ Area = ½ × BC × AD

→ Area = ½ × 6 × 9

→ Area = 3 × 9

→ Area = 27

Area of triangle = 27 cm²

Now, we have base i.e. AB and area of the triangle. So, we can find the altitude i.e. CE :-

→ Area = ½ × AB × CE

→ 27 = ½ × 7.5 × CE

→ 54 = 7.5 CE

→ CE = 54 / 7.5

→ CE = 7.2

Length of CE = 7.2 cm


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