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ABC is an isosceles triangle with coordinates of B and C as B( -4,0) and C(4,0) andAB=AC=5 units. Find the coordinates of the vertex A.PLEASE DON'T SPAM OR I WILL REPORT YOU

Answer»

ANSWER:

A(xy),B(-4,0),C(40)

Step-by-step explanation:

ab = \sqrt{(x + 4)^{2} + {(y - 0)}^{2} } \\ ac = \sqrt{ {(x - 4)}^{2} + (y - 0) ^{2} } \\ but \: ab = ac \\ {(x + 4)}^{2} + {y}^{2} = {(x - 4)}^{2} + {y}^{2} \\ {x}^{2} + 8x + 16 = {x}^{2} - 8x + 16 \\ 16x = 0 \\ x = 0 \\ ac ^{2} = {x}^{2} - 8x + 16 + y^{2} \\ 25 = 16 + {y }^{2} \\ y = 3 \\a (x.y) = (0.3)


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