ABC is a triangle where three lines are drawn through the vertices A,

1.	ABC is a triangle where three lines are drawn through the vertices A, B and C parallel to the sides BC, CA and AB respectively, forming PQR. Prove that BC = 1/2PR AC = 1/2 PQ AB = 1/2RQ
Answer» ong>Step-by-step explanation: AQ∥CB and AC∥QB ∴AQBC is a parallelogram ∴BC=AQ (Opposite side of a parallelogram) ∵AR∥BC and AB∥RC ∴ARCB is a parallelogram ∴BC=AR (Opposite side of a parallelogram) Hence A is the midpoint of QR Similarly B and C are MIDPOINTS of PQ and PR respectively ∴AB= 2 1 PRBC= 2 1 QRCA= 2 1 PQ 2AB=PR2BC=QR2CA=PQ PR+QR+PQ=2(AB+BC+CA) THEREFORE, Perimeter of △ PQR=2[Perimeter of △ABC] MARK me the brainliest

ABC is a triangle where three lines are drawn through the vertices A, B and C parallel to the sides BC, CA and AB respectively, forming PQR. Prove that BC = 1/2PR AC = 1/2 PQ AB = 1/2RQ

Answer»

ong>Step-by-step explanation:

AQ∥CB and AC∥QB

∴AQBC is a parallelogram

∴BC=AQ (Opposite side of a parallelogram)

∵AR∥BC and AB∥RC

∴ARCB is a parallelogram

∴BC=AR (Opposite side of a parallelogram)

Hence A is the midpoint of QR

Similarly B and C are MIDPOINTS of PQ and PR respectively

∴AB=

PRBC=

QRCA=

2AB=PR2BC=QR2CA=PQ

PR+QR+PQ=2(AB+BC+CA)

THEREFORE,

Perimeter of △ PQR=2[Perimeter of △ABC]

MARK me the brainliest

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ABC is a triangle where three lines are drawn through the vertices A, B and C parallel to the sides BC, CA and AB respectively, forming PQR. Prove that BC = 1/2PR AC = 1/2 PQ AB = 1/2RQ

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