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ABC is a triangle in which D is the mid-point of BC. E and F are mid-points of DC and AE respectively. If area of ΔABC is 16 cm2, find the area of ΔDEF. |
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Answer» Given that, D, E, F are the mid-points of BC, DC, AE respectively Let, AD is median of triangle ABC Area (ΔADC) = \(\frac{1}{2}\)Area (ΔABC) = \(\frac{1}{2}\) x 16 = 8 cm2 Now, AE is a median of ΔADC Area (ΔAED) = \(\frac{1}{2}\)Area (ΔADC) = \(\frac{1}{2}\) x 8 = 4 cm2 Again, DE is the median of ΔAED Area (ΔDEF) = \(\frac{1}{2}\)Area (ΔAED) = \(\frac{1}{2}\) x 4 = 2 cm2 |
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