∆ ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on same side of BC . If AD is extended to intersect BC at P show that AP is the perpendicular bisector of BC

∆ ABC and ∆DBC are two isosceles triangles on the same base BC and

1.	∆ ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on same side of BC . If AD is extended to intersect BC at P show that AP is the perpendicular bisector of BC
Answer» ∆ ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on same side of BC . If AD is extended to intersect BC at P show that AP is the perpendicular bisector of BC