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ABC and DBC are two isosceles triangles on the same base BC.Show that angle ABD=angle ACD |
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Answer» Step-by-step explanation: ∠ABD = ∠ABC + ∠CBD ∠ACD = ∠ACB + DCB Both the triangles are ISOSCELES, so the ANGLES FORMING at the BASE would be equal. So if ∠ABC = ∠ACB and ∠DBC = ∠BCD, the sum of ∠ABC + ∠DBC would be equal to the sum of ∠ACD and ∠BCD. Hence, proved. |
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