AB=Xcm, BC=x+4 and triangle ABC=48², Find BC, AD

1.	AB=Xcm, BC=x+4 and triangle ABC=48², Find BC, AD
Answer» Step-by-step explanation: TRIANGLE ABC AB = x BC = x - 4 AC = 10 angle BAC = 60 deg Using LAW of Cosines a^2 = b^2 + c^2 - 2BC cos A (x -4)^2 = 10^2 + x^2 - 2(10)(x)cos 60 x^2 - 8x + 16 = 100 + x^2 - 20X (0.5) x^2 - 8x + 16 = 100 + x^2 - 10x 2x = 84 x = 42

Answer»

Step-by-step explanation:

TRIANGLE ABC

AB = x

BC = x - 4

AC = 10

angle BAC = 60 deg

Using LAW of Cosines

a^2 = b^2 + c^2 - 2BC cos A

(x -4)^2 = 10^2 + x^2 - 2(10)(x)cos 60

x^2 - 8x + 16 = 100 + x^2 - 20X (0.5)

x^2 - 8x + 16 = 100 + x^2 - 10x

2x = 84

x = 42

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AB=Xcm, BC=x+4 and triangle ABC=48², Find BC, AD​

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AB=Xcm, BC=x+4 and triangle ABC=48², Find BC, AD