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AB is the diameter of a circle, centre O, C is a point on the circumference such that ∠COB = θ. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove thatsinθ2cosθ2=π12-θ120

Answer» AB is the diameter of a circle, centre O, C is a point on the circumference such that ∠COB = θ. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove that



sinθ2cosθ2=π12-θ120





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