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AB is the chord of the circle with centre O. If its radius OC intersects AB at M, OA= 10 cm, AB = 12cm, then MC = ______ |
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Answer» Answer: Answer OA is the radius of the circle Perpendicular drawn from centre to a chord bisects the chord. Therefore AM= 2 1
AB AM=10cm Thus, TRIANGLE OMA is right angled TRIANGLED at ∠OMA. ∠OMA=90 ∘ . By PYTHAGORAS THEOREM, OA 2 =OM 2 +MA 2
OA= OM 2 +MA 2
OA= (2 11
) 2 +10 2
OA= 144
cm OA=12cm Radius of a circle is 12cm. Option B will be the answer. |
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