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AB is a line segment and line L is its perpendicular bisector if point P lies on L show that equidistant from A and B |
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Answer» ong>Answer: SOLUTION 1: AB is a line SEGMENT and l is its perpendicular bisector. If a point P lies on l. Show that P is EQUIDISTANT from A and B. since , AB is a line segment, L is drawn perpendicular to AB, A point 'p' lies on line L. {To\: prove} : P is equidistant from A and B. {Prove} :- In ∆AOP and ∆BOP , OP = OP ( common side ) \anglePOA = \anglePOB AO = OB \therefore ∆AOP \cong ∆BOP (By S.A.S.) => AP = BP ( By C.P.C.T. ) Hence , "P" is equidistant from A and B . solution 2: |
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