AB is a chord of circle substending an angle 90 degrees at the center

1.	AB is a chord of circle substending an angle 90 degrees at the center O of the circle If the radius of the circle is 6cm the area of minor segment is
Answer» Answer: area of minor sector = area of chord - area of triangle area of chord = (Ф /360) X πr^2 = 9π area of triangle = 1/2 x B x h = 1/2 x 6 x 6 = 18 so ANS is 9π - 18 pls add to brainliest Step-by-step explanation:

AB is a chord of circle substending an angle 90 degrees at the center O of the circle If the radius of the circle is 6cm the area of minor segment is

Answer»

Answer:

area of minor sector = area of chord - area of triangle

area of chord = (Ф /360) X πr^2 = 9π

area of triangle = 1/2 x B x h = 1/2 x 6 x 6 = 18

so ANS is 9π - 18

pls add to brainliest

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AB is a chord of circle substending an angle 90 degrees at the center O of the circle If the radius of the circle is 6cm the area of minor segment is​

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AB is a chord of circle substending an angle 90 degrees at the center O of the circle If the radius of the circle is 6cm the area of minor segment is