AB|| CD , QO  6cm and OB 8cm, find OPOD.

1.	AB\|\| CD , QO  6cm and OB 8cm, find OPOD.
Answer» PERPENDICULAR drawn from centre of a circle to chord bisects the chord. AC=BC=12cm And ∠OCB=90 ∘ THUS, TRIANGLE OCB is a RIGHT ANGLED triangle OB=13cm. Therefore by Pythagoras theorem OB 2 =OC 2 +BC 2 OC 2 =OB 2 −BC 2 OC= 13 2 −12 2 OC=5cm

Answer»

PERPENDICULAR drawn from centre of a circle to chord bisects the chord.

AC=BC=12cm

And ∠OCB=90

∘

THUS, TRIANGLE OCB is a RIGHT ANGLED triangle

OB=13cm.

Therefore by Pythagoras theorem

=OC

+BC

=OB

−BC

OC=

−12

OC=5cm

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AB|| CD , QO  6cm and OB 8cm, find OPOD.

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