1.

AB, BC, CD and AD are the tangents of the circle. If AP = x, BP = y, CR = z, SD =w then show that the perimeter of the quadrilateral ABCD is 2(x + y + z + w).

Answer»

AP = AS = x;

BP = BQ = y

CR = CQ = z;

SD = DR = w

ie, AB = x + y

BC = y + z;

CD = z + w

AD = x + z

∴ Perimeter = 2x + 2y + 2z + 2w = 2(x + y + z + w)



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