1.

AB and CD are two parallel chords of a circle with centre O such that AB = 6 cm and CD = 12 cm. The chords are on the same side of the centre and the distance between them in 3 cm. The radius of the circle isA. 6 cm B. 5\(\sqrt2\) cm C. 7 cm D. 3\(\sqrt5\) cm

Answer»

Option : (D)

Given that, 

AB || CD 

(Chords on same side of centre) 

AO = CO (Radii) 

OL and OM perpendicular bisector of CD and AB respectively 

CL = LD = 6 cm 

AM = MB = 3 cm 

LM = 3 cm (Given) 

In COL, 

CO2 = OL2 + 62 ...(i) 

In AOM, 

AO2 = AM2 + OM2 

= 32 + (OL + LM)2 

= 9 + OL2 + 9 + 6O L 

OL2 = AO2 - 18 - 6O L ... (ii) 

Using (ii) in (i), 

OL = 3 cm 

Putting OL in (i),

AO2\(\sqrt{45}\)

 AO = 3\(\sqrt{5}\)



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