1.

AB and CD are two parallel chords and O is the centre. If AB = 24 cm,CD=18cm and radius by= 15 cm. Find the distance between the chords,if both the chords are:(i) on the opposite sides of the centre,(ii) on the same side of the centre.

Answer»

Answer:

In the FIGURE, chords AB∥CD

O is the centre of the circle

Radius of the Circle = 15 cm

Length of AB = 24 cm and CD = 18 cm

Join OA and OC

AM = MB = 24/2 = 12 cm

Similarly ON⊥CD

CN = ND = 18/2 = 9 cm

In right △AMO

OA

2

=OM

2

+AM

2

OM

2

=OA

2

−AM

2

OM

2

=15

2

+12

2

=225−144

OM=

81

=9

Similarly in right △CNO

OC

2

=CN

2

+ON

2

(15)

2

=(9)

2

+ON

2

225=81+ON

2

ON

2

=225−81

ON=12cm

Now MN=OM+ON=9+12=21cm



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