AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre then prove that 4q2=p2+3r2.

AB and AC are two chords of a circle of radius r such that AB = 2AC. I

1.	AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre then prove that 4q2=p2+3r2.
Answer» AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre then prove that $4 q^{2} = p^{2} + 3 r^{2}$ .