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A³-8b³+64c³+24abc factorize |
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Answer» Step-by-step EXPLANATION: Step-by-step explanation: =(a)³-(2B)³-(4C)³-3(a)(2b)(4c) =[a³-b³-c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca) =(a)³-(2b)³-(4c)³-3(a)(2b)(4c)=(a+2b+4c)[(a)²+(2b)²+(4c)²-(a)(2b)-(2b)(4c)-(4c)(a) =(a+2b+4c)(a²+4b²+16c²-2ab-8bc-4ca) ANSWER.. |
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