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a2 b2Solve for x and y:= 0a2b b2a |
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Answer» a^2/x - b^2/y = 0...................(1)a^2b/x + b^2a/y = a + b....... (2) Multiply eq(1) by aa^3/x - b^2a/y = 0.................(3) Add eq(2) and eq(3)a^3/x = a + bx = a^3/(a + b) Put value of x in eq(1), we geta^2 /[a^3/(a + b)] - b^2/y = 0(a + b)/a = b^2/yy = ab^2/(a + b) |
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