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A15meterslongladderreachedawindow12meter highfromthegroundonplacingitagainsta wallatadistance‘q’metersfromthefootofladder.Findthedistance(q)ofthefootoftheladderfromthewall |
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Answer» Answer: LET AC be the LADDER and A be the window. Given: AC=15m, AB=12m, CB=am In right angled triangle ACB, (Hypotenuse) =(Base) 2 +[Perpendicular) 2 [By Pythagoras theorem] ⇒(AC) 2 =(CB) 2 +(AB) 2
⇒(15) 2 =(a) 2 +(12) 2
⇒225=a 2 +144 ⇒a 2 =225−144=81 ⇒a= 81
=9cm Thus, the DISTANCE of the foot of the ladder from the wall is 9m. solution |
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