A Young’s double slit interference arrangement with slits S1 andS2is immersed in water (refractive index = 43) as shown in the figure. The position of maxima on the surface of water are given by x2=p2m2λ2−d2, where λ is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer. The value of p is

A Young’s double slit interference arrangement with slits S1 andS2is

1.	A Young’s double slit interference arrangement with slits S1 andS2is immersed in water (refractive index = 43) as shown in the figure. The position of maxima on the surface of water are given by x2=p2m2λ2−d2, where λ is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer. The value of p is
Answer» A Young’s double slit interference arrangement with slits $S_{1}$ and $S_{2}$ is immersed in water (refractive index = $\frac{4}{3})$ as shown in the figure. The position of maxima on the surface of water are given by $x^{2} = p^{2} m^{2} λ^{2} - d^{2},$ where $λ$ is the wavelength of light in air (refractive index = 1), 2d is the separation between the slits and m is an integer. The value of p is

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