A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index =4/3) as shown in the figure. The positions of maximum on the surface of water are given by x2=p2m2λ2−d2, where λ is the wavelength of light in air (refractive index =1), 2d is the separation between the slits and m is an integer. The value of p is

A Young's double slit interference arrangement with slits S1 and S2 is

1.	A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index =4/3) as shown in the figure. The positions of maximum on the surface of water are given by x2=p2m2λ2−d2, where λ is the wavelength of light in air (refractive index =1), 2d is the separation between the slits and m is an integer. The value of p is
Answer» A Young's double slit interference arrangement with slits $S_{1}$ and $S_{2}$ is immersed in water (refractive index $= 4 / 3)$ as shown in the figure. The positions of maximum on the surface of water are given by $x^{2} = p^{2} m^{2} λ^{2} - d^{2}$ , where $λ$ is the wavelength of light in air (refractive index $= 1$ ), $2 d$ is the separation between the slits and $m$ is an integer. The value of $p$ is

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