A={x:x is a facter of 24} and y= {x:x is a factor of 36} then verify n

1.	A={x:x is a facter of 24} and y= {x:x is a factor of 36} then verify n(AUB)+n(AnB)=n(A)+n(B)
Answer» Answer: Given, X is a set of FACTORS of 24 i.e., X={1,2,3,4,6,8,12,24} ALSO given, Y is a set of factors of 36 i.e., Y={1,2,3,4,6,9,12,18,36} THEREFORE, the SETS of X∪Y={1,2,3,4,6,8,9,12,18,24,36} and X∩Y={1,2,3,4,6,12}

A={x:x is a facter of 24} and y= {x:x is a factor of 36} then verify n(AUB)+n(AnB)=n(A)+n(B)

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Answer:

Given, X is a set of FACTORS of 24 i.e., X={1,2,3,4,6,8,12,24}

ALSO given, Y is a set of factors of 36 i.e., Y={1,2,3,4,6,9,12,18,36}

THEREFORE, the SETS of X∪Y={1,2,3,4,6,8,9,12,18,24,36}

and X∩Y={1,2,3,4,6,12}

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A={x:x is a facter of 24} and y= {x:x is a factor of 36} then verify n(AUB)+n(AnB)=n(A)+n(B)​

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A={x:x is a facter of 24} and y= {x:x is a factor of 36} then verify n(AUB)+n(AnB)=n(A)+n(B)