(a) Write the cell reaction and calculate the e.m.f of the following cell at 298 K : Sn(s) Sn2+ (0.004 M) || H+ (0.020 M) | H2(g) (1 bar) | Pt (s) (Given : E∘Sn2+/Sn = -0.14 V) (b) Give reasons : (i) On the basis of E∘ values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl. (ii) Conductivity of CH3COOH decreases on dilution.

(a) Write the cell reaction and calculate the e.m.f of the following c

1.	(a) Write the cell reaction and calculate the e.m.f of the following cell at 298 K : Sn(s) Sn2+ (0.004 M) \|\| H+ (0.020 M) \| H2(g) (1 bar) \| Pt (s) (Given : E∘Sn2+/Sn = -0.14 V) (b) Give reasons : (i) On the basis of E∘ values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl. (ii) Conductivity of CH3COOH decreases on dilution.
Answer» (a) Write the cell reaction and calculate the e.m.f of the following cell at 298 K : Sn(s) $S n^{2 +}$ (0.004 M) \|\| $H^{+}$ (0.020 M) \| $H_{2} (g)$ (1 bar) \| Pt (s) (Given : $E_{S n^{2 +} / S n}^{\circ}$ = -0.14 V) (b) Give reasons : (i) On the basis of $E^{\circ}$ values, $O_{2}$ gas should be liberated at anode but it is $C l_{2}$ gas which is liberated in the electrolysis of aqueous NaCl. (ii) Conductivity of $C H_{3} C O O H$ decreases on dilution.