A wooden box who's value is 1300₹ is fine wood cost is 25₹/m . len

1.	A wooden box who's value is 1300₹ is fine wood cost is 25₹/m . length of the box is 4m and breath is 3m find its height
Answer» ❏ CORRECT Question:- @ A wooden box who's value is 1300₹ is fine wood cost is 25₹/m² . length of the box is 4m and BREATH is 3m FIND its height ❏ Solution:- $\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(5.6,5.6){$A$}\put(11.1,5.8){$B$}\put(11.08,8.9){$C$}\put(5.46,8.7){$D$}\put(3.55,10.15){$E$}\put(3.55,7.15){$F$}\put(9.14,10.235){$H$}\put(9.14,7.3){$G$}\put(3.3,6.3){$3\:m$}\put(7.75,6.<klux>2</klux>){$4\:m$}\put(11.1,7.5){$h\:m$}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$ Now , according to the question The wooden box is cost 1300 Rs at 25 Rs/m². Therefore, Total Surface area of the wooden box is , = $\dfrac{1300}{25}\:Rs$ = 52 m². Now, we know that total surface area of a cuboid is , $\sf\implies T.S.A.=2(lb+bh+hl)$ where, T.S.A.=Total Surface area . l = length, b= breadth, h = height, Hence, $\sf\implies 52=2(4\times3+3\times h+h\times4)$ $\sf\implies \dfrac{\cancel{52}}{\cancel2}=12+3 h+4h$ $\sf\implies 26-12=3 h+4h$ $\sf\implies 14=7h$ $\sf\implies \dfrac{\cancel{14}}{\cancel7}=h$ $\sf\implies \boxed{\large{\red{h=2\:m}}}$ Hence , *Height of the Wooden Box was 2 METRE*.

A wooden box who's value is 1300₹ is fine wood cost is 25₹/m . length of the box is 4m and breath is 3m find its height

Answer»

❏ CORRECT Question:-

@ A wooden box who's value is 1300₹ is fine wood cost is 25₹/m² . length of the box is 4m and BREATH is 3m FIND its height

❏ Solution:-

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\thicklines\put(5.6,5.6){$A$}\put(11.1,5.8){$B$}\put(11.08,8.9){$C$}\put(5.46,8.7){$D$}\put(3.55,10.15){$E$}\put(3.55,7.15){$F$}\put(9.14,10.235){$H$}\put(9.14,7.3){$G$}\put(3.3,6.3){$3\:m$}\put(7.75,6.<klux>2</klux>){$4\:m$}\put(11.1,7.5){$h\:m$}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\put(6,6){\line(-3,2){2}}\put(6,9){\line(-3,2){2}}\put(11,9){\line(-3,2){2}}\put(11,6){\line(-3,2){2}}\end{picture}$