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A wooden block of volume `1000cm^(3)` is suspended from a spring balance its weight is 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance isA. `10 N`B. `9 N`C. `8 N`D. `7 N` |
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Answer» Correct Answer - D Reading of the spring balance = Apparent weight of the block = Actual weight - upthrust `= 12 - V_("in")sigmag` `=12-500xx10^(-6)xx10^(3)xx10=12-5 =7 N`. |
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