a wooden block of mass 0.010 kg is dropped from the top of a cliff 100 m high. simultaneously A bullet of mass 0.010 kg is fired from the foot of a cliff upward with a velocity of 100 m per second. the bullet and the wooden block will meet each other after the time in seconds is?

a wooden block of mass 0.010 kg is dropped from the top of a cliff 100

1.	a wooden block of mass 0.010 kg is dropped from the top of a cliff 100 m high. simultaneously A bullet of mass 0.010 kg is fired from the foot of a cliff upward with a velocity of 100 m per second. the bullet and the wooden block will meet each other after the time in seconds is?
Answer» HIIII dear________❤️❤️ good afternoon___________✌️✌️✌️✌️✌️ Let they MEET after t second If block travels 's'm distance then in same TIME the bullet travells(100-s)m For block s=0×t+12s=0×t+12×10×t2×10×t2 For bullet 100−s=100×t+12100−s=100×t+12(−10)×t2(−10)×t2 Solving this; we GET t=1second

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a wooden block of mass 0.010 kg is dropped from the top of a cliff 100 m high. simultaneously A bullet of mass 0.010 kg is fired from the foot of a cliff upward with a velocity of 100 m per second. the bullet and the wooden block will meet each other after the time in seconds is?

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