A woman throws an object of mass 500g with a speed of 25 ms^(-1) . (a) What is the impulse imparted to the object? (b) If the object hits a wall and rebounds with half the original speed what is the change in momentum of the object ?

A woman throws an object of mass 500g with a speed of 25 ms^(-1) . (a

1.	A woman throws an object of mass 500g with a speed of 25 ms^(-1) . (a) What is the impulse imparted to the object? (b) If the object hits a wall and rebounds with half the original speed what is the change in momentum of the object ?
Answer» SOLUTION :Here, ` m = 500 g = (1)/(2) KG , u = 25 ms^(-1) ` (a) Impulse IMPARTED = change in momentum = initial momentum given ` m u = (1)/(2) xx25 = 12.5 Ns ` (b) On rebounding force the wall ` UPSILON = -(1)/(2) xx 25 = - 12.5 m//s ` Change in momentum ` = m (upsilon- u ) = (1)/(2) (-12.5- 25) = - 18.75 kg ms^(-1)` .