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A with of length 50 cm moves with a velocity of 300 m/min, perpendicular to a magnetic fiel. If the emf induced in the wire is 2 V, then the magnitude of the field in tesla isA. 2B. 5C. `0.8`D. `2.5` |
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Answer» Correct Answer - C When a wire of length l moves with velocity v, perpendicular to a magnetic field B, then the induced emf is produced. The magnitude of induced emf is given by `|epsilon|=Blv`. Given l = 50 cm = 0.5 m, v = 300 m/min = 5 m/s `|epsilon|=2Vor B=(|epsilon|)/(lv)=(2)/(0.5xx5)=0.8T` |
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