1.

A wire that obeys Hooke.s law is of length L_(1) when it is in equilibrium under a tension F_(1)It.s length becomes L_(2) when the tension is increased to F_(2).Calculate the energy stored in the wire during this process.

Answer»

Solution :ENERGY stored = Area of SHADED region
`=(1)/(2)(F_(1)+F_(2))[(L_(1)-l)-(L_(1)-l)]=(1)/(2)(F_(1)+F_(2))(L_(2)-L_(1))`


Discussion

No Comment Found