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A wire of resistance (1 `Omega`) is divided into two halves and both halves are connected in parallel. Find the new resistance. |
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Answer» Resistance of each half `= (1 Omega)/(2) = 0.5 Omega` Since these two halves are in parallel, resultant resistance `= (0.5 Omega)/(2) = 0.25 Omega`. |
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