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A wire of length 5.0m and diameter 2.0mm extends by 0.25 mm when a force of 50N was used to stretch it from its endCalculate a. the stress on the wireb. strain in the wire |
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Answer» Explanation: L = 5 d = 2*10^-3 r = 10^-3 A = PI r^2 = pi (10^-6) STRESS = 50 N / 3.14*10^-6 = 15.9 * 10^6 Newtons/ m^2 strain = DELTA L/L = .25*10^-3 / 5 = .05 *10^-3 = 50 * 10^-6 m Hope it helps you! PLEASE mark me as the brainliest! |
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