A wire of length 4m placed normal to the magneticfield of (2i+4j) tesl

1.	A wire of length 4m placed normal to the magneticfield of (2i+4j) tesla is moving with a velocity(4i+6j+8k)The emf induced across the endsof the wire will be(1) 4 V(2) 8 v(3) 16 V(4) 32 V
Answer» answer : option (3) 16volts explanation : induced emf , $\xi$ = $(<klux>V</klux>\times B)$ L here it is GIVEN that wire of length 4m is normal to the plane of MAGNETIC field. so, L = 4k also, given, B = (2i + 4j) Tesla v = (4I + 6j + 8k) m/s = [(4i + 6j + 8k) × (2i + 4j + 0k)]. 4k = [i (6 × 0 - 8 × 4) - j(4 × 0 - 8 × 2) + k(4 × 4 - 6 × 2) ] × 4 = [-32i + 16j + 4k ]. 4k = 16 Volts hence, option (3) is correct choice.

A wire of length 4m placed normal to the magneticfield of (2i+4j) tesla is moving with a velocity(4i+6j+8k)The emf induced across the endsof the wire will be(1) 4 V(2) 8 v(3) 16 V(4) 32 V

Answer»

answer : option (3) 16volts

explanation : induced emf , $\xi$ = $(<klux>V</klux>\times B)$ L

here it is GIVEN that wire of length 4m is normal to the plane of MAGNETIC field.

so, L = 4k

also, given, B = (2i + 4j) Tesla

v = (4I + 6j + 8k) m/s

= [(4i + 6j + 8k) × (2i + 4j + 0k)]. 4k

= [i (6 × 0 - 8 × 4) - j(4 × 0 - 8 × 2) + k(4 × 4 - 6 × 2) ] × 4

= [-32i + 16j + 4k ]. 4k

= 16 Volts

hence, option (3) is correct choice.

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A wire of length 4m placed normal to the magneticfield of (2i+4j) tesla is moving with a velocity(4i+6j+8k)The emf induced across the endsof the wire will be(1) 4 V(2) 8 v(3) 16 V(4) 32 V​

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A wire of length 4m placed normal to the magneticfield of (2i+4j) tesla is moving with a velocity(4i+6j+8k)The emf induced across the endsof the wire will be(1) 4 V(2) 8 v(3) 16 V(4) 32 V