1.

A wire of length 140 cm is bent into a rectangle. If the length of the rectangle is 10 cm more than its breadth, find the area of the rectangle.

Answer»

Answer:

The required area of the RECTANGLE is 1200 cm²

Step-by-step explanation:

Given :

  • A wire of length 140 cm is bent into a rectangle.
  • The length of the rectangle is 10 cm more than its breadth.

To find :

the area of the rectangle

Solution :

As the wire is bent into a shape of rectangle, the length of the wire is equal to the perimeter of the rectangle.

we know,

Perimeter of the rectangle = 2(Length + breadth)

Let 'l cm' be the length of the rectangle and 'b cm' be the breadth of the rectangle.

As given,

l = (b + 10) cm

Length of the wire = perimeter of the rectangle

140 cm = 2(l + b)

140 = 2(b + 10 + b)

140 = 2(2b + 10)

140/2 = 2b + 10

70 = 2b + 10

2b = 70 – 10

2b = 60

b = 60/2

b = 30 cm

The breadth of the rectangle is 30 cm.

Now, let's find the length of the rectangle.

length = 10 + 30 = 40 cm

Area of the rectangle = length × breadth

= 40 cm × 30 cm

= 1200 cm²


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